JEE Chemistry 2025 Question with Solution

Given: List-I contains isomers of $C_{10}H_{14}$ and List-II contains the possible ozonolysis products.

Find: The correct matching between the isomers and their ozonolysis products.

Ozonolysis cleaves the carbon-carbon double bond and gives carbonyl compounds. Depending on substitution at the double-bond carbons, the products can be aldehydes, ketones, or a mixture of aldehyde and ketone.

From the provided solution analysis, the matches are:

• (A) Cyclohexene derivative $\rightarrow$ (II) Diketone product
• (B) 1,2-Dimethylcyclohexene $\rightarrow$ (IV) Aldehyde product
• (C) 1-Methylcyclohexene $\rightarrow$ (I) Aldehyde product
• (D) 1,4-Dimethylcyclohexene $\rightarrow$ (III) Aldehyde and ketone product

Thus the correct matching is (A)-(II), (B)-(IV), (C)-(I), (D)-(III).

Therefore, the correct option is B.

Given: Ozonolysis breaks the $\text{C=C}$ bond and converts the two alkene carbons into carbonyl centers.

Find: Which option reproduces the matching stated in the solution.

The solution explicitly concludes the following mapping:

1. (A) Cyclohexene derivative $\rightarrow$ (II) Diketone product
2. (B) 1,2-Dimethylcyclohexene $\rightarrow$ (IV) Aldehyde product
3. (C) 1-Methylcyclohexene $\rightarrow$ (I) Aldehyde product
4. (D) 1,4-Dimethylcyclohexene $\rightarrow$ (III) Aldehyde and ketone product

Comparing this with the answer choices, only Option B matches exactly:

(A)-(II), (B)-(IV), (C)-(I), (D)-(III).

Therefore, the correct option is B.