The magnetic intensity at the center of a long current carrying solenoid is found to be 1.6 10^3 A/m. If the number of t

Question

The magnetic intensity at the center of a long current carrying solenoid is found to be 1.6 10^3 A/m. If the number of turns is 8 per cm, then the current flowing through the solenoid is:

Accepted Answer

Given: Magnetic intensity at the center of the solenoid is $H = 1.6 \times 10^3 \, \text{A/m}$ and the number of turns is $n = 8 \, \text{turns/cm} = 800 \, \text{turns/m}$ .

Find: The current $I$ flowing through the solenoid.

For a long current carrying solenoid, magnetic intensity is given by

H = nI

So,

I = \frac{H}{n} = \frac{1.6 \times 10^3}{800} = 2 \, \text{A}

Therefore, the current flowing through the solenoid is $2 \, \text{A}$ .

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