MCQMediumJEE Main 2025 · 24 January, Shift 2Ampere's Law

Physics Question from JEE Main 2025 · 24 January, Shift 2

A circle of radius R carrying N equally spaced charges rotates with angular velocity omega; a larger Amperian loop B encloses the whole circle and a smaller loop A encloses a small segment.

N equally spaced charges each of value qq are placed on a circle of radius RR. The circle rotates about its axis with an angular velocity ω\omega as shown in the figure. A bigger Amperian loop BB encloses the whole circle, whereas a smaller Amperian loop AA encloses a small segment. The difference between enclosed currents, IAIBI_A - I_B, for the given Amperian loops is:

  • A

    2πNqω\frac{2\pi}{N} q\omega

  • B

    N22πqω\frac{N^2}{2\pi} q\omega

  • C

    Nπqω\frac{N}{\pi} q\omega

  • D

    N2πqω\frac{N}{2\pi} q\omega

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