MCQMediumJEE Main 2025 · 29 January, Shift 1Ampere's Law

Physics Question from JEE Main 2025 · 29 January, Shift 1

Consider a long straight wire of a circular cross-section (radius aa) carrying a steady current II. The current is uniformly distributed across this cross-section. The distances from the centre of the wire's cross-section at which the magnetic field (inside the wire, outside the wire) is half of the maximum possible magnetic field, anywhere due to the wire, will be:

  • A

    [a2,3a]\left[ \frac{a}{2}, 3a \right]

  • B

    [a2,2a]\left[ \frac{a}{2}, 2a \right]

  • C

    [a4,2a]\left[ \frac{a}{4}, 2a \right]

  • D

    [a4,3a2]\left[ \frac{a}{4}, \frac{3a}{2} \right]

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