NVAMediumJEE Main 2023 · 8 April, Shift 1Circle Equation & Properties

Mathematics Question from JEE Main 2023 · 8 April, Shift 1

Consider a circle C1:x2+y24x2y=α5C_1 : x^2 + y^2 - 4x - 2y = \alpha - 5. Let its mirror image in the line y=2x+1y = 2x + 1 be another circle C2:5x2+5y210fx10gy+36=0C_2 : 5x^2 + 5y^2 - 10fx - 10gy + 36 = 0. Let rr be the radius of C2C_2. Then α+r\alpha + r is equal to:

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