MCQMediumJEE Main 2023 · 8 April, Shift 1Trigonometric Ratios & Identities

Mathematics Question from JEE Main 2023 · 8 April, Shift 1

Let f(x)=sinx+cosx2sinxcosxf(x) = \frac{\sin x + \cos x - \sqrt{2}}{\sin x - \cos x}, where x[0,π]{π4}x \in [0, \pi] - \left\{\frac{\pi}{4}\right\}. Then f(7π12)f(7π12)f\left(\frac{7\pi}{12}\right) \cdot f''\left(\frac{7\pi}{12}\right) is equal to:

  • A

    23\frac{-2}{3}

  • B

    29\frac{2}{9}

  • C

    133\frac{-1}{3\sqrt{3}}

  • D

    233\frac{2}{3\sqrt{3}}

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