MCQMediumJEE Main 2023 · 8 April, Shift 1Cross Product

Mathematics Question from JEE Main 2023 · 8 April, Shift 1

If the points with position vectors αi^+10j^+13k^\alpha \hat{i} + 10\hat{j} + 13\hat{k}, 6i^+11j^+11k^6\hat{i} + 11\hat{j} + 11\hat{k}, and 92i^+βj^8k^\frac{9}{2}\hat{i} + \beta\hat{j} - 8\hat{k} are collinear, then (19α6β)2(19\alpha - 6\beta)^2 is equal to:

  • A

    4949

  • B

    3636

  • C

    2525

  • D

    1616

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