MCQMediumJEE Main 2023 · 6 April, Shift 1Cross Product

Mathematics Question from JEE Main 2023 · 6 April, Shift 1

Let the position vectors of the points A, B, C and D be 5i+5j+2λk5\mathbf{i} + 5\mathbf{j} + 2\lambda \mathbf{k}, i+2j+3k\mathbf{i} + 2\mathbf{j} + 3\mathbf{k}, 2i+λj+4k-2\mathbf{i} + \lambda\mathbf{j} + 4\mathbf{k} and i+5j+6k-\mathbf{i} + 5\mathbf{j} + 6\mathbf{k}. Let the set S={λR:S = \{\lambda \in \mathbb{R}: the points A, B, C and D are coplanar}\}. Then λS(λ+2)2\sum_{\lambda \in S}(\lambda + 2)^2 is equal to:

  • A

    372\frac{37}{2}

  • B

    1313

  • C

    2525

  • D

    4141

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