Physics Question from JEE Main 2023 · 1 February, Shift 2

Moment of inertia of a disc of mass $M$ and radius $R$ about any of its diameter is $\frac{MR^2}{4}$. The moment of inertia of this disc about an axis normal to the disc and passing through a point on its edge will be, $\frac{x}{2} MR^2$. The value of $x$ is _____.