Physics Question from JEE Main 2023 · 25 January, Shift 1

$I_{CM}$ is the moment of inertia of a circular disc about an axis (CM) passing through its center and perpendicular to the plane of the disc. $I_{AB}$ is its moment of inertia about an axis $AB$ perpendicular to the plane and parallel to axis $CM$ at a distance $\frac{2}{3} R$ from the center, where $R$ is the radius of the disc. The ratio of $I_{AB}$ and $I_{CM}$ is $x : 9$. The value of $x$ is: