MCQMediumJEE 2023Biot–Savart Law

JEE Physics 2023 Question with Solution

Find the magnetic field at the point PP in the figure. The curved portion is a semicircle connected to two long straight wires.

Figure showing a semicircular curved wire connected to a long horizontal wire at the top and a long vertical wire downward, with current $$I$$ marked and point $$P$$ near the center.Duplicate overlay of the same wire figure showing the semicircular arc, two straight wires, current direction $$I$$, and point $$P$$ inside the semicircle.
  • A

    μ0I2r(1+2π)\frac{\mu_0 I}{2r} \left( 1 + \frac{2}{\pi} \right)

  • B

    μ0I2r(1+1π)\frac{\mu_0 I}{2r} \left( 1 + \frac{1}{\pi} \right)

  • C

    μ0I2r(12+12π)\frac{\mu_0 I}{2r} \left( \frac{1}{2} + \frac{1}{2\pi} \right)

  • D

    μ0I2r(1+1π)\frac{\mu_0 I}{2r} \left( 1 + \frac{1}{\pi} \right)

Answer

Correct answer:C

Step-by-step solution

Standard Method

Given: A semicircular curved wire of radius rr is connected to two long straight wires carrying current II. The magnetic field is required at point PP.

Find: Magnetic field at PP.

Applying Biot-Savart’s Law:

Bp=(μ0I4r+μ0I4πr)=μ0I2r(12+12π)B_p = \left( \frac{\mu_0 I}{4r} + \frac{\mu_0 I}{4\pi r} \right) = \frac{\mu_0 I}{2r} \left( \frac{1}{2} + \frac{1}{2\pi} \right)

Therefore, the magnetic field at PP is μ0I2r(12+12π)\frac{\mu_0 I}{2r} \left( \frac{1}{2} + \frac{1}{2\pi} \right). This matches option C. The solution labels option D, but the worked expression matches option C, so the worked expression is taken as authoritative.

Common mistakes

  • Adding the option label from the page instead of checking the worked expression is incorrect. The final formula from the solution must be matched with the options; here it matches option C, not the listed label D.

  • Using the magnetic field formula for a full circle instead of a semicircle is incorrect. For the curved part, use the semicircular contribution shown in the working, not the full circular field.

  • Ignoring the contribution of the straight wire segments is incorrect. The total field at PP is obtained by adding the contributions written in the solution expression.

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