NVAEasyJEE Main 2023 · 31 January, Shift 1Cross Product

Mathematics Question from JEE Main 2023 · 31 January, Shift 1

Let a⃗\vec{a} and b⃗\vec{b} be two vectors such that

∣a⃗∣=14,∣b⃗∣=6,∣a⃗×b⃗∣=48.|\vec{a}| = \sqrt{14}, \quad |\vec{b}| = \sqrt{6}, \quad |\vec{a} \times \vec{b}| = \sqrt{48}.

Then (a⃗⋅b⃗)2(\vec{a} \cdot \vec{b})^2 is equal to:

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