MCQMediumJEE 2023Carboxylic Acids

JEE Chemistry 2023 Question with Solution

Consider the following reaction Propanal + Methanal(i)dil. NaOH(ii)A(iii)NaCN(iv)H2OProduct B(C5H8O3)\text{Propanal + Methanal} \xrightarrow{(i)\, \text{dil. NaOH}} \xrightarrow{(ii)\, A} \xrightarrow{(iii)\, \text{NaCN}} \xrightarrow{(iv)\, H_2O} \text{Product B} \, (C_5H_8O_3)

The correct statement for product BB is:

  • A

    Optically active and adds one mole of bromine

  • B

    Racemic mixture and is neutral

  • C

    Racemic mixture and gives a gas with saturated NaHCO3\text{NaHCO}_3 solution

  • D

    Optically active alcohol and is neutral

Answer

Correct answer:C

Step-by-step solution

Standard Method

Given: The sequence starts from propanal and methanal and finally gives product BB with molecular formula C5H8O3C_5H_8O_3.

Find: The correct statement about product BB.

From the solution text, the reaction sequence is interpreted as formation of an aldol-type product first, followed by reaction with NaCN\text{NaCN} and then hydrolysis to give a carboxylic acid containing a stereogenic center.

The key conclusions explicitly stated in the solution are:

  1. The final product is a racemic mixture.
  2. The final product contains a carboxylic acid group.
  3. A carboxylic acid reacts with saturated NaHCO3\text{NaHCO}_3 solution to release CO2CO_2 gas.

Therefore, the correct statement for product BB is: it is a racemic mixture and gives a gas with saturated NaHCO3\text{NaHCO}_3 solution.

The correct option is C.

Concept Check

Given: Product BB is obtained after reaction with NaCN\text{NaCN} followed by hydrolysis.

Find: Which property matches the final product.

Reaction with NaCN\text{NaCN} generally introduces a nitrile functionality through cyanide addition/substitution. On hydrolysis, the nitrile is converted into a carboxylic acid. Hence the final product is acidic rather than neutral.

Since a new chiral center is formed and no chiral reagent is used, the product is obtained as a racemic mixture rather than as a single optically active form.

An acidic compound containing COOH-COOH reacts with saturated NaHCO3\text{NaHCO}_3 to evolve CO2CO_2 gas. Hence the statement matching product BB is option C.

Common mistakes

  • Assuming the final product is neutral after hydrolysis. Hydrolysis of a nitrile gives a carboxylic acid, so the product is acidic. Check the functional group change before choosing the option.

  • Marking the product as optically active instead of racemic. Formation of a chiral center in an achiral environment usually gives both enantiomers in equal amounts, so the product is racemic.

  • Confusing NaHCO3\text{NaHCO}_3 test with general acidity. Alcohols do not evolve gas with saturated NaHCO3\text{NaHCO}_3, but carboxylic acids do because they release CO2CO_2.

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