JEE Physics 2023 Question with Solution

Given: A combination of NOT, AND, and OR gates is shown. Find: Which truth table gives the correct output $X$.

The solution states that the inputs $A$ and $B$ are first inverted by the NOT gates, then combined through AND gates, and finally passed through the OR gate.

From the extracted truth table analysis:

• When $A = 0$ and $B = 0$, $X = 1$
• When $A = 0$ and $B = 1$, $X = 0$
• When $A = 1$ and $B = 0$, $X = 1$
• When $A = 1$ and $B = 1$, $X = 0$

So the required truth table is:

$$\begin{array}{c c c} A & B & X \\ 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \\ 1 & 1 & 0 \end{array}$$

This matches Table 3.

Therefore, the correct option is C.

Given: Four table options are provided as images. Find: Which one matches the output pattern stated in the solution.

Compare the rows one by one:

1. For $A = 0$, $B = 0$, output must be $1$.
2. For $A = 0$, $B = 1$, output must be $0$.
3. For $A = 1$, $B = 0$, output must be $1$.
4. For $A = 1$, $B = 1$, output must be $0$.

Among the given image options, only option C shows the sequence:

$$1, 0, 1, 0$$

for the rows

$$(0,0), (0,1), (1,0), (1,1)$$

respectively.

Hence, the correct option is C.