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MCQMediumJEE Main 2023 · 25 January, Shift 2Cross Product

Mathematics Question from JEE Main 2023 · 25 January, Shift 2

Let a⃗=−i^−j^+k^\vec{a} = -\hat{i} - \hat{j} + \hat{k}, a⃗⋅b⃗=1\vec{a} \cdot \vec{b} = 1 and a⃗×b⃗=i^−j^\vec{a} \times \vec{b} = \hat{i} - \hat{j}. Then a⃗−6b⃗\vec{a} - 6\vec{b} is equal to:

  • A

    3(i^−j^−k^)3(\hat{i} - \hat{j} - \hat{k})

  • B

    3(i^+j^+k^)3(\hat{i} + \hat{j} + \hat{k})

  • C

    3(i^−j^+k^)3(\hat{i} - \hat{j} + \hat{k})

  • D

    3(i^+j^−k^)3(\hat{i} + \hat{j} - \hat{k})

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