MCQMediumJEE Main 2023 · 25 January, Shift 1Biot–Savart Law

Physics Question from JEE Main 2023 · 25 January, Shift 1

Match List I (current configuration) with List II (magnetic field at point OO).

The four configurations AA, BB, CC and DD of List I are shown in the figure below.

Four current-carrying wire configurations labelled A, B, C and D, each built from long straight segments joined by a circular loop or a semicircular arc of radius r centred on the point O, with the current direction marked by arrows.
List I (Current configuration)List II (Magnetic field at point OO)
(A) Straight wire carrying II that makes one complete circular loop of radius rr about OO before continuing in the same line(I) B0=μ0I4πr[π+2]B_0 = \dfrac{\mu_0 I}{4\pi r}\left[\pi + 2\right]
(B) Two long straight wires, a distance 2r2r apart, joined at one end by a semicircular arc of radius rr centred at OO(II) B0=μ04IrB_0 = \dfrac{\mu_0}{4}\dfrac{I}{r}
(C) A semicircular arc of radius rr about OO with one straight lead at perpendicular distance rr and the other lying along a line through OO(III) B0=μ0I2πr[π1]B_0 = \dfrac{\mu_0 I}{2\pi r}\left[\pi - 1\right]
(D) A semicircular arc of radius rr about OO with both straight leads lying along the diameter through OO(IV) B0=μ0I4πr[π+1]B_0 = \dfrac{\mu_0 I}{4\pi r}\left[\pi + 1\right]

Choose the correct answer from the option given below:

  • A

    A-III, B-IV, C-I, D-II

  • B

    A-I, B-III, C-IV, D-II

  • C

    A-III, B-I, C-IV, D-II

  • D

    A-II, B-I, C-IV, D-III

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