The points of intersection of the line ax + by = 0, (a ≠ b) and t… | JEE Main 2023 Mathematics PYQ

MCQMediumJEE Main 2023 · 25 January, Shift 1Circle Equation & Properties

The points of intersection of the line $ax + by = 0$ , $(a \neq b)$ and the circle $x^2 + y^2 - 2x = 0$ are $A(\alpha, 0)$ and $B(1, \beta)$ . The image of the circle with $AB$ as a diameter in the line $x + y + 2 = 0$ is:

A
$x^2 + y^2 + 5x + 5y + 12 = 0$
B
$x^2 + y^2 + 3x + 5y + 8 = 0$
C
$x^2 + y^2 + 3x + 3y + 4 = 0$
D
$x^2 + y^2 - 5x - 5y + 12 = 0$

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