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JEE Chemistry 2023 Question with Solution

The hybridization and magnetic behaviour of cobalt ion in [Co(NH3)6]3+[Co(NH_3)_6]^{3+} complex is:

  • A

    sp2sp^2 and diamagnetic

  • B

    d3d^3 and paramagnetic

  • C

    d5d^5 and diamagnetic

  • D

    d2s2d^2 s^2 and paramagnetic

Answer

Correct answer:C

Step-by-step solution

Standard Method

Given: The complex is [Co(NH3)6]3+[Co(NH_3)_6]^{3+}.

Find: The hybridization and magnetic behaviour of the cobalt ion in this complex.

Cobalt is in the +3+3 oxidation state, so its electronic configuration is [Ar]3d6[Ar]3d^6. Since NH3NH_3 is a strong field ligand, it causes pairing of the 3d3d electrons. Therefore, the complex becomes an inner orbital octahedral complex with hybridization

d2sp3d^2sp^3

All electrons are paired, so the complex is diamagnetic.

The solution marks option C as correct, but the extracted option text is inconsistent with the working. The chemically correct description is d2sp3d^2sp^3 and diamagnetic.

Option Discrepancy Noted

Given: [Co(NH3)6]3+[Co(NH_3)_6]^{3+} contains cobalt in the +3+3 state.

Find: Which listed option best matches the actual hybridization and magnetic behaviour.

From the solution:

  1. Cobalt in [Co(NH3)6]3+[Co(NH_3)_6]^{3+} is Co3+Co^{3+}.
  2. Its configuration is [Ar]3d6[Ar]3d^6.
  3. NH3NH_3 is a strong field ligand, so pairing occurs.
  4. The complex uses inner orbitals and has
d2sp3d^2sp^3

hybridization. 5. Hence all electrons are paired and the complex is diamagnetic.

Therefore, the worked solution supports diamagnetic behaviour with d2sp3d^2sp^3 hybridization. However, none of the listed options states this exactly. Since the solution explicitly declares option C, the answer is recorded as C while noting the mismatch between the options and the explanation.

Common mistakes

  • Assuming NH3NH_3 is always a weak field ligand is incorrect. In this complex, it acts as a strong enough field ligand for Co3+Co^{3+} to pair the 3d3d electrons. Check the metal ion and oxidation state before deciding high spin or low spin behaviour.

  • Using the neutral cobalt configuration instead of the configuration of Co3+Co^{3+} gives the wrong electron count. First find the oxidation state, then write the correct dd-electron configuration.

  • Choosing an option only by matching the word diamagnetic without checking the hybridization is incomplete. Both the magnetic behaviour and the orbital hybridization must agree with the electron pairing argument.

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