JEE Chemistry 2026 Question with Solution

Given: Statements about the nature and hybridization of five coordination complexes are listed.

Find: Which set of statements is correct.

Use ligand field strength and the electronic configuration of the metal ion to determine whether the complex is inner orbital or outer orbital, and then identify the hybridization.

For A:

is a strong field ligand, so the complex is low spin and forms an inner orbital octahedral complex with

hybridization. Hence A is correct.

For B:

is a weak field ligand, so the complex is high spin and octahedral with outer orbital

hybridization. Hence B is correct.

For C:

is a weak field ligand, so the complex is high spin and octahedral with

hybridization, not

Therefore C is incorrect.

For D:

is a weak field ligand, so the complex is high spin and octahedral with outer orbital

hybridization. Hence D is correct.

For E:

is a strong field ligand. The complex $[Ni(CN)_4]^{2-}$ is square planar with

hybridization, not

Therefore E is incorrect.

So the correct details are A, B and D only. Therefore, the correct option is C.

Given: The complexes $[Co(NH_3)_6]^{3+}$, $[MnCl_6]^{3-}$, $[CoF_6]^{3-}$, $[FeF_6]^{3-}$ and $[Ni(CN)_4]^{2-}$.

Find: Which statements match the correct inner/outer orbital description and hybridization.

Key classifications used in the solution:

• Inner octahedral complex $\rightarrow d^2sp^3$
• Outer octahedral complex $\rightarrow sp^3d^2$
• Square planar complex $\rightarrow dsp^2$
• Tetrahedral complex $\rightarrow sp^3$

The solution explicitly states:

• A is correct
• B is correct
• C is incorrect because it should be $sp^3d^2$
• D is correct
• E is incorrect because it should be $dsp^2$

Hence the valid set is A, B and D only, which matches option C.