MCQMediumJEE Main 2026 · 28 January, Shift 2Velocity & Acceleration

Physics Question from JEE Main 2026 · 28 January, Shift 2

A particle starts moving from time t=0t=0 and its coordinate is given as x(t)=4t33t.x(t)=4t^3-3t. Consider the following statements:

[A.] The particle returns to its original position (origin) 0.8660.866 units later. [B.] The particle is 11 unit away from origin at its turning point. [C.] Acceleration of the particle is non-negative. [D.] The particle is 0.50.5 units away from origin at its turning point. [E.] The particle never turns back as acceleration is non-negative.

Choose the correct answer from the options given below:

  • A

    C, E Only

  • B

    A, B, C Only

  • C

    A, C, D Only

  • D

    A, C Only

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