MCQEasyJEE Main 2024 · 27 January, Shift 1Velocity & Acceleration

Physics Question from JEE Main 2024 · 27 January, Shift 1

Position of an ant (SS in metres) moving in the YZY-Z plane is given by S=2t2j^+5k^S = 2t^2 \hat{j} + 5 \hat{k} (where tt is in seconds). The magnitude and direction of velocity of the ant at t=1st = 1 \, \text{s} will be:

  • A

    16m/s16 \, \text{m/s} in yy-direction

  • B

    4m/s4 \, \text{m/s} in xx-direction

  • C

    9m/s9 \, \text{m/s} in zz-direction

  • D

    4m/s4 \, \text{m/s} in yy-direction

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