The position vector of a moving body at any instant of time is given as r = ( 5t² i - 5t j) m. The magnitude a…

Question

The position vector of a moving body at any instant of time is given as $$\mathbf{r} = \left( 5t^2 \hat{i} - 5t \hat{j} ight) \, 	ext{m}$$. The magnitude and direction of velocity at $$t = 2 \, 	ext{s}$$ is:

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A. $$5\sqrt{17} \, 	ext{m/s}$$, making an angle of $$	an^{-1}(4)$$ with the $$-\hat{y}$$ axis

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B. $$5\sqrt{15} \, 	ext{m/s}$$, making an angle of $$	an^{-1}(4)$$ with the $$-\hat{y}$$ axis

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C. $$5\sqrt{15} \, 	ext{m/s}$$, making an angle of $$	an^{-1}(4)$$ with the $$+\hat{x}$$ axis

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D. $$5\sqrt{17} \, 	ext{m/s}$$, making an angle of $$	an^{-1}(4)$$ with the $$+\hat{x}$$ axis

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