MCQEasyJEE Main 2026 · 28 January, Shift 1Integrated Rate Laws

Chemistry Question from JEE Main 2026 · 28 January, Shift 1

An organic compound undergoes first order decomposition. The time taken for decomposition to 18\dfrac{1}{8} and 110\dfrac{1}{10} of its initial concentration are t1/8t_{1/8} and t1/10t_{1/10} respectively. Find the value of t1/8t1/10×10\frac{t_{1/8}}{t_{1/10}}\times10

(Given: log2=0.3\log 2 = 0.3)

  • A

    33

  • B

    3030

  • C

    99

  • D

    0.90.9

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