Chemistry Question from JEE Main 2026 · 28 January, Shift 1

At temperature $T$ K, $2$ moles of liquid $A$ and $3$ moles of liquid $B$ are mixed. The vapour pressure of the ideal solution formed is $320$ mm Hg. At this stage, one mole of $A$ and one mole of $B$ are added to the solution. The vapour pressure is now measured as $328.6$ mm Hg. The vapour pressures (in mm Hg) of pure $A$ and pure $B$ respectively are: