MCQEasyJEE Main 2025 · 2 April, Shift 1Raoult's Law & Vapour Pressure

Chemistry Question from JEE Main 2025 · 2 April, Shift 1

A solution is made by mixing one mole of volatile liquid AA with 33 moles of volatile liquid BB. The vapor pressure of pure AA is 200mm Hg200 \, \text{mm Hg} and that of the solution is 500mm Hg500 \, \text{mm Hg}. The vapor pressure of pure BB and the least volatile component of the solution, respectively, are:

  • A

    1400mm Hg1400 \, \text{mm Hg}, AA

  • B

    1400mm Hg1400 \, \text{mm Hg}, BB

  • C

    600mm Hg600 \, \text{mm Hg}, AA

  • D

    600mm Hg600 \, \text{mm Hg}, BB

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Raoult's Law & Vapour Pressure questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions