MCQEasyJEE Main 2026 · 24 January, Shift 2First Law & Internal Energy

Physics Question from JEE Main 2026 · 24 January, Shift 2

10 mole of an ideal gas is undergoing the cyclic process described below, drawn on a PP-VV diagram with PP in Pa\text{Pa} and VV in m3\text{m}^3 (the volume axis is marked at 11, 22, 33, 44 and 55): the gas is first taken along the constant-volume line V=1m3V = 1 \, \text{m}^3 from P1P_1 up to P2P_2, then expanded along a falling curve from V=1m3V = 1 \, \text{m}^3 out to V=5m3V = 5 \, \text{m}^3, then dropped vertically at V=5m3V = 5 \, \text{m}^3, and finally compressed along a lower curve back to the starting state (V=1m3, P=P1)(V = 1 \, \text{m}^3,\ P = P_1). The heat involved in the process from P1P_1 to P2P_2 is α\alpha Joule (P1=21.7Pa,  P2=30Pa,  Cv=21J/Kmol,  R=8.3J/molK)(P_1 = 21.7 \, \text{Pa},\; P_2 = 30 \, \text{Pa},\; C_v = 21 \, \text{J/K}\cdot\text{mol},\; R = 8.3 \, \text{J/mol}\cdot\text{K}). The value of α\alpha is _____.

  • A

    1515

  • B

    2121

  • C

    2828

  • D

    2424

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