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MCQMediumJEE Main 2026 · 28 January, Shift 1First Law & Internal Energy

Physics Question from JEE Main 2026 · 28 January, Shift 1

In the following p–Vp\text{–}V diagram, the equation of state along the curved path is given by (V−2)2=4ap,(V-2)^2 = 4ap, where aa is a constant. The total work done in the closed path is:

A p-V diagram with pressure on vertical axis and volume on horizontal axis, showing points A at V=1, C at V=3 on a horizontal line, and a curved path through B below them forming a closed loop.
  • A

    −13a-\dfrac{1}{3a}

  • B

    +13a+\dfrac{1}{3a}

  • C

    12a\dfrac{1}{2a}

  • D

    −1a-\dfrac{1}{a}

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