Elements X and Y belong to Group . The difference between the electronegativity values of 'X' and phosphorus is higher than that of the difference between phosphorus and 'Y'. 'X' & 'Y' are respectively
- A
As & Bi
- B
Bi & N
- C
As & Sb
- D
N & As
MCQEasyJEE 2026Electron Gain Enthalpy & Electronegativity
JEE Chemistry 2026 Question with Solution
Answer
Correct answer:D
Step-by-step solution
Standard Method
Given: X and Y are Group elements, and we need
Find: The correct pair X and Y.
Group elements are N, P, As, Sb, Bi. Electronegativity decreases down the group.
The largest change in electronegativity in this group occurs between the first two members, N and P, while the change further down the group is smaller.
Testing option D: X = N and Y = As.
Then,
is the difference between a 2nd period and 3rd period element, which is relatively large.
And,
is the difference between a 3rd period and 4th period element, which is smaller.
Since
the condition
holds true.
Therefore, the correct option is D.
Common mistakes
Assuming electronegativity decreases by the same amount down the entire group is incorrect. The drop from N to P is larger than the drop between lower consecutive members. Compare relative changes, not just the direction of trend.
Ignoring the absolute value signs is a mistake. The question asks for the magnitude of the difference in electronegativity, so compare and , not signed values.
Choosing elements below phosphorus for both X and Y is incorrect because then the larger difference with phosphorus is less likely. Check which element gives the maximum separation from phosphorus within Group .
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