MCQMediumJEE 2026First Law & Internal Energy

JEE Physics 2026 Question with Solution

The internal energy of a monoatomic gas is 3nRT3nRT. One mole of helium... heated slowly by supplying 126J126 \, \text{J} heat... piston will move _____ cm.

  • A

    15.515.5

  • B

    1.551.55

  • C

    1.451.45

  • D

    14.514.5

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: Internal energy is given as U=3nRTU = 3nRT. One mole of helium is heated slowly, so the process is isobaric. Heat supplied is Q=126JQ = 126 \, \text{J}.

Find: The displacement of the piston.

From

U=3nRTU = 3nRT

we get

Cv=3RC_v = 3R

Therefore,

Cp=Cv+R=4RC_p = C_v + R = 4R

Using the extracted solution working

For an isobaric process,

Q=nCpΔT=n(3R+R)ΔTQ = n C_p \Delta T = n(3R+R)\Delta T

So the extracted working gives

Q=4WQ = 4W

which implies

W=Q4=1264=31.5JW = \frac{Q}{4} = \frac{126}{4} = 31.5 \, \text{J}

Option discrepancy noted in source solution

The source solution then explicitly switches to

W=1265=25.2JW = \frac{126}{5} = 25.2 \, \text{J}

and uses

W=PAΔxW = PA\Delta x

with

P=105Pa,A=17×104m2P = 10^5 \, \text{Pa}, \quad A = 17 \times 10^{-4} \, \text{m}^2

Thus,

25.2=105×17×104×Δx25.2 = 10^5 \times 17 \times 10^{-4} \times \Delta x

so

Δx=25.2170=0.148m=14.8cm\Delta x = \frac{25.2}{170} = 0.148 \, \text{m} = 14.8 \, \text{cm}

Hence the closest option is 14.514.5, so the correct option is D.

Note: The extracted solution contains an internal inconsistency: it first obtains W=31.5JW = 31.5 \, \text{J} from Cp=4RC_p = 4R, but then uses W=25.2JW = 25.2 \, \text{J} to match the options. Since the source solution concludes with option D, the answer is taken as D.

Common mistakes

  • Using only Q=ΔUQ = \Delta U here is incorrect because the piston moves, so work is also done. In an isobaric process, use the heat relation and the work relation together.

  • Taking CvC_v and CpC_p interchangeably is wrong. First infer CvC_v from U=3nRTU = 3nRT, then use Cp=Cv+RC_p = C_v + R.

  • Forgetting unit conversion from metre to centimetre gives a wrong final value. After finding Δx\Delta x in metres, convert it to centimetres before matching options.

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