NVAMediumJEE Main 2026 · 23 January, Shift 1Faraday's Laws of EMI

Physics Question from JEE Main 2026 · 23 January, Shift 1

A simple pendulum made of mass 10g10 \, \text{g} and a metallic wire of length 10cm10 \, \text{cm} is suspended vertically in a uniform magnetic field of 2T2 \, \text{T}. The magnetic field direction is perpendicular to the plane of oscillations of the pendulum. If the pendulum is released from an angle of 6060^\circ with vertical, then maximum induced EMF between the point of suspension and point of oscillation is _____ mV\text{mV}. (Take g=10m/s2g = 10 \, \text{m/s}^2)

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Faraday's Laws of EMI questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions