MCQEasyJEE Main 2026 · 23 January, Shift 1Faraday's Laws of EMI

Physics Question from JEE Main 2026 · 23 January, Shift 1

Match List-I with List-II.

List-I (Relation)List-II (Law)
(A) Edl=ddtBda\oint \vec{E} \cdot d\vec{l} = -\frac{d}{dt}\oint \vec{B} \cdot d\vec{a}(I) Ampere's circuital law
(B) Bdl=μ0(I+ε0dϕEdt)\oint \vec{B} \cdot d\vec{l} = \mu_0\left(I + \varepsilon_0 \frac{d\phi_E}{dt}\right)(II) Faraday's laws of electromagnetic induction
(C) Eda=1ε0Vρdv\oint \vec{E} \cdot d\vec{a} = \frac{1}{\varepsilon_0}\int_V \rho\, dv(III) Ampere - Maxwell law
(D) Bdl=μ0I\oint \vec{B} \cdot d\vec{l} = \mu_0 I(IV) Gauss's law of electrostatics

Choose the correct answer from the options given below :

  • A

    A-II, B-III, C-I, D-IV

  • B

    A-I, B-IV, C-III, D-II

  • C

    A-IV, B-I, C-II, D-III

  • D

    A-II, B-III, C-IV, D-I

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