JEE Physics 2026 Question with Solution

Given: A matching question between equations in List-I and laws in List-II.

Find: The correct correspondence between the equations and the named laws.

From the solution text:

• A: $\oint \vec{E} \cdot d\vec{l} = -\frac{d\Phi_B}{dt}$ corresponds to Faraday's law of electromagnetic induction, so A \rightarrow II.
• B: $\oint \vec{B} \cdot d\vec{l} = \mu_0 \left(I + \varepsilon_0 \frac{d\Phi_E}{dt}\right)$ corresponds to Ampere-Maxwell law, so B \rightarrow III.
• C: $\iint \vec{E} \cdot d\vec{a} = \frac{Q_{\text{encl}}}{\varepsilon_0}$ corresponds to Gauss's law of electrostatics, so C \rightarrow IV.
• D: $\oint \vec{B} \cdot d\vec{l} = \mu_0 I$ corresponds to Ampere's circuital law, so D \rightarrow I.

Therefore, the correct matching is A-II, B-III, C-IV, D-I.

The correct option is D.

Given: The equations in List-I are standard Maxwell-equation forms.

Find: The law name matched to each equation.

A quick identification method is to look for the special term in each equation:

• If the equation contains $-\frac{d\Phi_B}{dt}$, it is Faraday's law.
• If the equation contains $\varepsilon_0 \frac{d\Phi_E}{dt}$ along with current $I$, it is Ampere-Maxwell law.
• If electric flux equals enclosed charge divided by $\varepsilon_0$, it is Gauss's law of electrostatics.
• If $\oint \vec{B} \cdot d\vec{l} = \mu_0 I$, it is Ampere's circuital law.

Hence, A-II, B-III, C-IV, D-I, so the correct option is D.