MCQEasyJEE 2026Young's Modulus, Bulk & Rigidity Modulus

JEE Physics 2026 Question with Solution

The strain-stress plot for materials A, B, C and D is shown in the figure. Which material has the largest Young's modulus?

Strain on the vertical axis and stress on the horizontal axis, with four straight lines from the origin labeled A, B, D, and C in decreasing slope order.
  • A

    A

  • B

    C

  • C

    B

  • D

    D

Answer

Correct answer:A

Step-by-step solution

Standard Method

Given: A strain-stress plot for materials A, B, C and D is shown.

Find: Which material has the largest Young's modulus.

Young's modulus is

Y=stressstrainY = \frac{\text{stress}}{\text{strain}}

In a strain-stress graph, the slope is

slope=strainstress=1Y\text{slope} = \frac{\text{strain}}{\text{stress}} = \frac{1}{Y}

So, the material with the smallest slope has the largest Young's modulus.

From the figure, line A is the flattest relative to the stress axis among the labeled materials according to the solution explanation, so it has the largest Young's modulus.

Therefore, the correct option is A.

Using the axis interpretation carefully

Given: The graph is strain on Y-axis and stress on X-axis.

Find: The material with maximum Young's modulus.

A common confusion is to treat this as a stress-strain graph. But here the axes are reversed.

For Young's modulus,

Y=σϵY = \frac{\sigma}{\epsilon}

Hence on this graph,

ϵσ=1Y\frac{\epsilon}{\sigma} = \frac{1}{Y}

This means:

  • larger slope \Rightarrow smaller YY
  • smaller slope \Rightarrow larger YY

The solution states that material A has the least steep slope relative to the stress axis, while D is steeper. Therefore A has the highest value of Young's modulus.

Thus, the correct option is A.

Common mistakes

  • Mistake: Treating the graph as a stress-strain graph and choosing the steepest line. Why it is wrong: the given axes are reversed. What to do instead: first check which quantity is on each axis, then relate slope to the required physical quantity.

  • Mistake: Using Y=strainstressY = \frac{\text{strain}}{\text{stress}}. Why it is wrong: Young's modulus is defined as stress divided by strain. What to do instead: write Y=stressstrainY = \frac{\text{stress}}{\text{strain}} and then invert the graph slope if the plot is strain versus stress.

  • Mistake: Assuming the visually steepest line always means the strongest or stiffest material. Why it is wrong: steepness depends on what is plotted on the axes. What to do instead: express the slope mathematically in terms of stress and strain before comparing materials.

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