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MCQMediumJEE Main 2026 · 22 January, Shift 2Alcohols

Chemistry Question from JEE Main 2026 · 22 January, Shift 2

Reaction scheme: cyclohexylmethanamine, $$\mathrm{C_6H_{11}CH_2NH_2}$$, drawn as a cyclohexane ring bearing a $$\mathrm{-CH_2NH_2}$$ group, is treated with $$\mathrm{C_6H_5COCl}$$ and $$\mathrm{NaOH}$$ to give intermediate $$[A]$$, which is then treated with $$\mathrm{LiAlH_4}$$ followed by $$\mathrm{H_2O}$$ to give product $$[B]$$.

The final product [B][\mathrm{B}] is:

  • A

    C6H5-CH2-NH-CO-cyclohexyl\text{C}_6\text{H}_5\text{-CH}_2\text{-NH-CO-cyclohexyl}

  • B

    Cyclohexyl-CH2-NH-CO-C6H5\text{Cyclohexyl-CH}_2\text{-NH-CO-C}_6\text{H}_5

  • C

    Cyclohexyl-CH2-NH-CH2-C6H5\text{Cyclohexyl-CH}_2\text{-NH-CH}_2\text{-C}_6\text{H}_5

  • D

    Cyclohexyl-CH2-NH-CH(OH)-C6H5\text{Cyclohexyl-CH}_2\text{-NH-CH(OH)-C}_6\text{H}_5

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