NVAMediumJEE Main 2026 · 22 January, Shift 1Gibbs Free Energy & Equilibrium Constant

Chemistry Question from JEE Main 2026 · 22 January, Shift 1

Dissociation of a gas A2A_2 takes place according to the following chemical reaction. At equilibrium, the total pressure is 1bar1 \, \text{bar} at 300K300 \, \text{K}.

A2(g)2A(g)A_2(\text{g}) \rightleftharpoons 2A(\text{g})

The standard Gibbs energy of formation of the involved substances is given below:

Substance ΔGf\Delta G_f^\circ (kJ mol1\text{kJ mol}^{-1}) A2A_2 100.00-100.00 AA 50.832-50.832

The degree of dissociation of A2(g)A_2(\text{g}) is given by (x×102)1/2\left(x \times 10^{-2}\right)^{1/2} where x=x = _____ (Nearest integer).

[Given: R=8J mol1K1R = 8 \, \text{J mol}^{-1}\text{K}^{-1}, log2=0.3010\log 2 = 0.3010, log3=0.48\log 3 = 0.48. Assume degree of dissociation is not negligible.]

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