MCQEasyJEE Main 2024 · 27 January, Shift 1Gibbs Free Energy & Equilibrium Constant

Chemistry Question from JEE Main 2024 · 27 January, Shift 1

For a reaction, if the equilibrium constant at 500 K500 \, \text{K} is 44, then the value of the standard Gibbs free energy ΔG∘\Delta G^\circ at this temperature is:

  • A

    −1155 J-1155 \, \text{J}

  • B

    1386 J1386 \, \text{J}

  • C

    −1386 J-1386 \, \text{J}

  • D

    1155 J1155 \, \text{J}

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