MCQMediumJEE Main 2025 · 8 April, Shift 2Limits

Mathematics Question from JEE Main 2025 · 8 April, Shift 2

Given below are two statements:

Statement I: limx0(tan1x+loge1+x1x2xx5)=25\lim_{x \to 0} \left( \frac{\tan^{-1} x + \log_e \sqrt{\frac{1+x}{1-x}} - 2x}{x^5} \right) = \frac{2}{5}

Statement II: limx1(x21x)=1e2\lim_{x \to 1} \left( x^{\frac{2}{1-x}} \right) = \frac{1}{e^2}

In the light of the above statements, choose the correct answer from the options given below

  • A

    Both Statement I and Statement II are false

  • B

    Statement I is false but Statement II is true

  • C

    Both Statement I and Statement II are true

  • D

    Statement I is true but Statement II is false

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