MCQMediumJEE Main 2026 · 24 January, Shift 1Limits

Mathematics Question from JEE Main 2026 · 24 January, Shift 1

If the function f(x)=ex(etanxx1)+loge(secx+tanx)xtanxxf(x)=\frac{e^x\left(e^{\tan x - x}-1\right)+\log_e(\sec x+\tan x)-x}{\tan x-x} is continuous at x=0x=0, then the value of f(0)f(0) is equal to

  • A

    23\dfrac{2}{3}

  • B

    32\dfrac{3}{2}

  • C

    22

  • D

    12\dfrac{1}{2}

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