MCQMediumJEE Main 2025 · 23 January, Shift 2Limits

Mathematics Question from JEE Main 2025 · 23 January, Shift 2

Evaluate the following limit: limx(2x23x+5)(3x1)x/2(3x2+5x+4)(3x+2)x.\lim_{x \to \infty} \frac{(2x^2 - 3x + 5) \left( 3x - 1 \right)^{x/2}}{(3x^2 + 5x + 4) \sqrt{(3x + 2)^x}}. The value of the limit is:

  • A

    23e\frac{2}{\sqrt{3e}}

  • B

    2e3\frac{2e}{\sqrt{3}}

  • C

    2e3\frac{2e}{3}

  • D

    23e\frac{2}{3\sqrt{e}}

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