MCQEasyJEE Main 2025 · 8 April, Shift 2Sum of Series

Mathematics Question from JEE Main 2025 · 8 April, Shift 2

If 114+124+134+=π490,\frac{1}{1^4} + \frac{1}{2^4} + \frac{1}{3^4} + \dots \infty = \frac{\pi^4}{90}, 114+134+154+=α,\frac{1}{1^4} + \frac{1}{3^4} + \frac{1}{5^4} + \dots \infty = \alpha, 124+144+164+=β,\frac{1}{2^4} + \frac{1}{4^4} + \frac{1}{6^4} + \dots \infty = \beta, then αβ\frac{\alpha}{\beta} is equal to:

  • A

    2323

  • B

    1515

  • C

    1414

  • D

    1818

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