MCQMediumJEE Main 2026 · 21 January, Shift 2Sum of Series

Mathematics Question from JEE Main 2026 · 21 January, Shift 2

The positive integer nn, for which the solutions of the equation x(x+2)+(x+2)(x+4)++(x+2n2)(x+2n)=8n3x(x+2) + (x+2)(x+4) + \dots + (x+2n-2)(x+2n) = \frac{8n}{3} are two consecutive even integers, is :

  • A

    99

  • B

    33

  • C

    1212

  • D

    66

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