MCQMediumJEE Main 2026 · 24 January, Shift 1Sum of Series

Mathematics Question from JEE Main 2026 · 24 January, Shift 1

Let 729,81,9,1,729, 81, 9, 1, \ldots be a sequence and PnP_n denote the product of the first nn terms of this sequence. If 2n=140(Pn)1n=3α13β2 \sum_{n=1}^{40} (P_n)^{\frac{1}{n}} = \frac{3^{\alpha} - 1}{3^{\beta}} and gcd(α,β)=1\gcd(\alpha, \beta) = 1, then α+β\alpha + \beta is equal to

  • A

    7373

  • B

    7575

  • C

    7676

  • D

    7474

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