MCQMediumJEE Main 2025 · 7 April, Shift 2Basics of Vectors

Mathematics Question from JEE Main 2025 · 7 April, Shift 2

Let a\vec{a} and b\vec{b} be the vectors of the same magnitude such that a+b+aba+bab=2+1.\frac{| \vec{a} + \vec{b} | + | \vec{a} - \vec{b} |}{| \vec{a} + \vec{b} | - | \vec{a} - \vec{b} |} = \sqrt{2} + 1. Then a+b2a2\frac{| \vec{a} + \vec{b} |^2}{| \vec{a} |^2} is:

  • A

    2+422 + 4\sqrt{2}

  • B

    1+21 + \sqrt{2}

  • C

    2+22 + \sqrt{2}

  • D

    4+224 + 2\sqrt{2}

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Basics of Vectors questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions