MCQMediumJEE Main 2025 · 23 January, Shift 1Basics of Vectors

Mathematics Question from JEE Main 2025 · 23 January, Shift 1

Let the position vectors of the vertices A, B, and C of a tetrahedron ABCD be i^+2j^+k^\hat{i} + 2\hat{j} + \hat{k}, i^+3j^2k^\hat{i} + 3\hat{j} - 2\hat{k}, and 2i^+j^k^2\hat{i} + \hat{j} - \hat{k} respectively. The altitude from the vertex D to the opposite face ABC meets the median line segment through A of the triangle ABC at the point E. If the length of AD is 1103\frac{\sqrt{110}}{3} and the volume of the tetrahedron is 80562\frac{\sqrt{805}}{6\sqrt{2}}, then the position vector of E is:

  • A

    12(i^+4j^+7k^)\frac{1}{2}(\hat{i} + 4\hat{j} + 7\hat{k})

  • B

    112(7i^+4j^+3k^)\frac{1}{12}(7\hat{i} + 4\hat{j} + 3\hat{k})

  • C

    16(12i^+12j^+k^)\frac{1}{6}(12\hat{i} + 12\hat{j} + \hat{k})

  • D

    16(7i^+12j^+k^)\frac{1}{6}(7\hat{i} + 12\hat{j} + \hat{k})

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