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MCQEasyJEE Main 2025 · 4 April, Shift 2Wave Motion Basics

Physics Question from JEE Main 2025 · 4 April, Shift 2

Displacement of a wave is expressed as x(t)=5cos⁡(628t+π2) m.x(t) = 5 \cos \left( 628t + \frac{\pi}{2} \right) \, \text{m}. The wavelength of the wave when its velocity is 300 m/s300 \, \text{m/s} is:

  • A

    5 m5 \, \text{m}

  • B

    3 m3 \, \text{m}

  • C

    0.5 m0.5 \, \text{m}

  • D

    0.33 m0.33 \, \text{m}

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