MCQEasyJEE 2025Wave Motion Basics

JEE Physics 2025 Question with Solution

Consider the sound wave travelling in ideal gases of He\mathrm{He}, CH4\mathrm{CH}_{4}, and CO2\mathrm{CO}_{2}. All the gases have the same ratio Pρ\frac{\mathrm{P}}{\rho}, where PP is the pressure and ρ\rho is the density. The ratio of the speed of sound through the gases vHe:vCH4:vCO2\mathrm{v}_{\mathrm{He}}: \mathrm{v}_{\mathrm{CH}_{4}}: \mathrm{v}_{\mathrm{CO}_{2}} is given by

  • A

    75:53:43\sqrt{\frac{7}{5}}: \sqrt{\frac{5}{3}}: \sqrt{\frac{4}{3}}

  • B

    53:43:75\sqrt{\frac{5}{3}}: \sqrt{\frac{4}{3}}: \sqrt{\frac{7}{5}}

  • C

    53:43:43\sqrt{\frac{5}{3}}: \sqrt{\frac{4}{3}}: \sqrt{\frac{4}{3}}

  • D

    43:53:75\sqrt{\frac{4}{3}}: \sqrt{\frac{5}{3}}: \sqrt{\frac{7}{5}}

Answer

Correct answer:C

Step-by-step solution

Standard Method

Given: Sound waves travel in ideal gases He\mathrm{He}, CH4\mathrm{CH}_{4} and CO2\mathrm{CO}_{2}, and all gases have the same ratio Pρ\frac{P}{\rho}.

Find: The ratio vHe:vCH4:vCO2v_{\mathrm{He}}:v_{\mathrm{CH}_{4}}:v_{\mathrm{CO}_{2}}.

For an ideal gas, the speed of sound is

vsound=γPρv_{\text{sound}} = \sqrt{\frac{\gamma P}{\rho}}

Since Pρ\frac{P}{\rho} is the same for all three gases, the speed depends only on γ\sqrt{\gamma}.

The ratios of specific heats are:

  • γHe=53\gamma_{\mathrm{He}} = \frac{5}{3}
  • γCH443\gamma_{\mathrm{CH}_{4}} \approx \frac{4}{3}
  • γCO243\gamma_{\mathrm{CO}_{2}} \approx \frac{4}{3}

Therefore,

vHe:vCH4:vCO2=53:43:43v_{\mathrm{He}}:v_{\mathrm{CH}_{4}}:v_{\mathrm{CO}_{2}} = \sqrt{\frac{5}{3}}: \sqrt{\frac{4}{3}}: \sqrt{\frac{4}{3}}

Hence, the correct option is C.

Why only gamma matters here

The expression

v=γPρv = \sqrt{\frac{\gamma P}{\rho}}

can be written for each gas as:

vHe=γHePρ,vCH4=γCH4Pρ,vCO2=γCO2Pρv_{\mathrm{He}} = \sqrt{\gamma_{\mathrm{He}}\frac{P}{\rho}}, \quad v_{\mathrm{CH}_{4}} = \sqrt{\gamma_{\mathrm{CH}_{4}}\frac{P}{\rho}}, \quad v_{\mathrm{CO}_{2}} = \sqrt{\gamma_{\mathrm{CO}_{2}}\frac{P}{\rho}}

Because the factor Pρ\frac{P}{\rho} is common, it cancels in the ratio. So,

vHe:vCH4:vCO2=γHe:γCH4:γCO2v_{\mathrm{He}}:v_{\mathrm{CH}_{4}}:v_{\mathrm{CO}_{2}} = \sqrt{\gamma_{\mathrm{He}}}:\sqrt{\gamma_{\mathrm{CH}_{4}}}:\sqrt{\gamma_{\mathrm{CO}_{2}}}

Substituting the given values of γ\gamma gives

53:43:43\sqrt{\frac{5}{3}}: \sqrt{\frac{4}{3}}: \sqrt{\frac{4}{3}}

Therefore, the correct option is C.

Common mistakes

  • Using molecular mass directly is incorrect here because the condition Pρ\frac{P}{\rho} is already the same for all gases. In this question, the speed ratio depends only on γ\gamma, so compare γ\sqrt{\gamma} values instead.

  • Assuming all gases have different values of Pρ\frac{P}{\rho} is wrong because the question explicitly states that this ratio is the same for all gases. Do not reintroduce extra dependence once the common factor cancels in the ratio.

  • Confusing the values of specific heat ratio is a common error. Helium is monatomic, so γ=53\gamma = \frac{5}{3}, while CH4\mathrm{CH}_{4} and CO2\mathrm{CO}_{2} are polyatomic and are taken approximately as 43\frac{4}{3} here.

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