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MCQEasyJEE Main 2025 · 23 January, Shift 2Wave Motion Basics

Physics Question from JEE Main 2025 · 23 January, Shift 2

The equation of a transverse wave travelling along a string is y(x,t)=4.0sin⁡(20×10−3x+600t)y(x, t) = 4.0 \sin \left( 20 \times 10^{-3} x + 600t \right) mm, where xx is in mm and tt is in seconds. The velocity of the wave is:

  • A

    +30 m/s+30 \, \text{m/s}

  • B

    −60 m/s-60 \, \text{m/s}

  • C

    −30 m/s-30 \, \text{m/s}

  • D

    +60 m/s+60 \, \text{m/s}

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