MCQMediumJEE Main 2025 · 4 April, Shift 2Sum of Series

Mathematics Question from JEE Main 2025 · 4 April, Shift 2

If the sum of the first 2020 terms of the series 414+312+14+424+322+24+434+332+34+444+342+44+\frac{4\cdot 1}{4 + 3\cdot 1^2 + 1^4} + \frac{4\cdot 2}{4 + 3\cdot 2^2 + 2^4} + \frac{4\cdot 3}{4 + 3\cdot 3^2 + 3^4} + \frac{4\cdot 4}{4 + 3\cdot 4^2 + 4^4} + \dots is mn\frac{m}{n}, where mm and nn are coprime, then m+nm + n is equal to:

  • A

    423423

  • B

    420420

  • C

    421421

  • D

    422422

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