MCQMediumJEE 2025Isomerism in Coordination Compounds

JEE Chemistry 2025 Question with Solution

Number of stereoisomers possible for the complexes, [CrCl3(py)3]\left[\mathrm{CrCl}_{3}(\mathrm{py})_{3}\right] and [CrCl2(ox)2]3\left[\mathrm{CrCl}_{2}(\mathrm{ox})_{2}\right]^{3-} are respectively

(py = pyridine, ox = oxalate)

  • A

    3&33 \& 3

  • B

    2&22 \& 2

  • C

    2&32 \& 3

  • D

    1&21 \& 2

Answer

Correct answer:C

Step-by-step solution

Standard Method

Given: The complexes are [CrCl3(py)3]\left[\mathrm{CrCl}_{3}(\mathrm{py})_{3}\right] and [CrCl2(ox)2]3\left[\mathrm{CrCl}_{2}(\mathrm{ox})_{2}\right]^{3-}.

Find: The number of stereoisomers possible for each complex.

For [CrCl3(py)3]\left[\mathrm{CrCl}_{3}(\mathrm{py})_{3}\right], chromium is coordinated by six ligands, so the complex has octahedral geometry. This is of the type [MA3B3][\mathrm{MA}_{3}\mathrm{B}_{3}].

For an octahedral complex of the type [MA3B3][\mathrm{MA}_{3}\mathrm{B}_{3}], two geometrical arrangements are possible:

  • fac isomer
  • mer isomer

Hence, [CrCl3(py)3]\left[\mathrm{CrCl}_{3}(\mathrm{py})_{3}\right] has 2 stereoisomers.

For [CrCl2(ox)2]3\left[\mathrm{CrCl}_{2}(\mathrm{ox})_{2}\right]^{3-}, oxalate is a bidentate ligand, so the complex is again octahedral. The two chloride ligands can be arranged in cis and trans forms.

The trans form is not optically active. The cis form is chiral and gives a pair of enantiomers.

So the total number of stereoisomers is:

1 trans+2 cis optical isomers=31\text{ trans} + 2\text{ cis optical isomers} = 3

Therefore, the numbers of stereoisomers are 22 and 33 respectively. The correct option is C.

Geometrical and Optical Isomer Counting

Given: Stereoisomers include geometrical and optical isomers.

Find: Count all stereoisomers for both complexes.

  1. For [CrCl3(py)3]\left[\mathrm{CrCl}_{3}(\mathrm{py})_{3}\right]:
  • It is an octahedral complex.
  • It belongs to the type [MA3B3][\mathrm{MA}_{3}\mathrm{B}_{3}].
  • Such complexes show facial (fac) and meridional (mer) isomerism.

Hence, total stereoisomers = 22.

  1. For [CrCl2(ox)2]3\left[\mathrm{CrCl}_{2}(\mathrm{ox})_{2}\right]^{3-}:
  • It is an octahedral complex with two chloride ligands and two bidentate oxalato ligands.
  • Geometrical isomers: cis and trans.
  • The cis arrangement is optically active and exists as two non-superimposable mirror images.
  • The trans arrangement is not optically active.

Hence, total stereoisomers =

1+2=31 + 2 = 3

Therefore, the required pair is 2&32 \& 3, so the correct option is C.

Common mistakes

  • Counting only geometrical isomers for [CrCl2(ox)2]3\left[\mathrm{CrCl}_{2}(\mathrm{ox})_{2}\right]^{3-} is incorrect. The cis form is optically active, so its two enantiomers must also be counted. Always include both geometrical and optical isomerism when asked for stereoisomers.

  • Assuming [CrCl3(py)3]\left[\mathrm{CrCl}_{3}(\mathrm{py})_{3}\right] has only one arrangement is wrong. An octahedral [MA3B3][\mathrm{MA}_{3}\mathrm{B}_{3}] complex can exist in both fac and mer forms. Check the standard octahedral isomer patterns before counting.

  • Treating the trans form of [CrCl2(ox)2]3\left[\mathrm{CrCl}_{2}(\mathrm{ox})_{2}\right]^{3-} as optically active is incorrect. The trans arrangement has symmetry and is not chiral. Only the cis form gives an optical pair here.

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