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MCQEasyJEE Main 2025 · 4 April, Shift 1Mean Free Path & Avogadro's Number

Physics Question from JEE Main 2025 · 4 April, Shift 1

The mean free path and the average speed of oxygen molecules at 300 K300 \, \text{K} and 1 atm1 \, \text{atm} are 3×10−7 m3 \times 10^{-7} \, \text{m} and 600 m/s600 \, \text{m/s}, respectively. Find the frequency of its collisions.

  • A

    2×1010/s2 \times 10^{10} / \mathrm{s}

  • B

    9×109/s9 \times 10^{9} / \mathrm{s}

  • C

    2×109/s2 \times 10^{9} / \mathrm{s}

  • D

    5×108/s5 \times 10^{8} / \mathrm{s}

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